6x^2+7x-25=30

Solution for 6x^2+7x-25=30 equation:

6x^2+7x-25=30

We move all terms to the left:

6x^2+7x-25-(30)=0

We add all the numbers together, and all the variables

6x^2+7x-55=0

a = 6; b = 7; c = -55;
Δ = b2-4ac
Δ = 72-4·6·(-55)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-37}{2*6}=\frac{-44}{12}
=-3+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+37}{2*6}=\frac{30}{12}
=2+1/2
$